Solving Word Problems With Equations Worksheet

Solving Word Problems With Equations Worksheet-10
According to the question; Ron will be twice as old as Aaron. Complement of x = 90 - x Given their difference = 12°Therefore, (90 - x) - x = 12°⇒ 90 - 2x = 12⇒ -2x = 12 - 90⇒ -2x = -78⇒ 2x/2 = 78/2⇒ x = 39Therefore, 90 - x = 90 - 39 = 51 Therefore, the two complementary angles are 39° and 51°9. If the table costs more than the chair, find the cost of the table and the chair. Solution: Let the number be x, then 3/5 ᵗʰ of the number = 3x/5Also, 1/2 of the number = x/2 According to the question, 3/5 ᵗʰ of the number is 4 more than 1/2 of the number.

Easing into algebra is easier than you think, and simple word problems that correspond to basic algebra is one way to introduce 5th and 6th grade students to this topic area.

The worksheets in this section are broken into pre-algebra problems by operation, and have the basic 'find the missing number' form.

The free, printable worksheets below will give students a chance to work problems and fill in their answers in the provided blank spaces.

Once the students have completed the work, use the worksheets to do quick formative assessments for an entire math class.

Algebra word problems that use standard math vocabulary to describe relationships between numbers in addition and subtraction problems.

Great for basic pre-algebra thinking skills, even before your grade school student starts algebra!Worked-out word problems on linear equations with solutions explained step-by-step in different types of examples. Solution: Then the other number = x 9Let the number be x. Therefore, x 4 = 2(x - 5 4) ⇒ x 4 = 2(x - 1) ⇒ x 4 = 2x - 2⇒ x 4 = 2x - 2⇒ x - 2x = -2 - 4⇒ -x = -6⇒ x = 6Therefore, Aaron’s present age = x - 5 = 6 - 5 = 1Therefore, present age of Ron = 6 years and present age of Aaron = 1 year.5. Then the other multiple of 5 will be x 5 and their sum = 55Therefore, x x 5 = 55⇒ 2x 5 = 55⇒ 2x = 55 - 5⇒ 2x = 50⇒ x = 50/2 ⇒ x = 25 Therefore, the multiples of 5, i.e., x 5 = 25 5 = 30Therefore, the two consecutive multiples of 5 whose sum is 55 are 25 and 30. The difference in the measures of two complementary angles is 12°. ⇒ 3x/5 - x/2 = 4⇒ (6x - 5x)/10 = 4⇒ x/10 = 4⇒ x = 40The required number is 40.There are several problems which involve relations among known and unknown numbers and can be put in the form of equations. Sum of two numbers = 25According to question, x x 9 = 25⇒ 2x 9 = 25⇒ 2x = 25 - 9 (transposing 9 to the R. S changes to -9) ⇒ 2x = 16⇒ 2x/2 = 16/2 (divide by 2 on both the sides) ⇒ x = 8Therefore, x 9 = 8 9 = 17Therefore, the two numbers are 8 and 17.2. A number is divided into two parts, such that one part is 10 more than the other. Try to follow the methods of solving word problems on linear equations and then observe the detailed instruction on the application of equations to solve the problems.It costs 0 to sign up plus for each ice-time.What is the maximum number of ice-times that Chantelle can go to. Their difference = 48According to the question, 7x - 3x = 48 ⇒ 4x = 48 ⇒ x = 48/4 ⇒ x = 12Therefore, 7x = 7 × 12 = 84 3x = 3 × 12 = 36 Therefore, the two numbers are 84 and 36.3. If the perimeter is 72 metre, find the length and breadth of the rectangle.More solved examples with detailed explanation on the word problems on linear equations.6. After 5 years, father will be three times as old as Robert. Underlying operations include addition, subtraction, multiplication and division of whole numbers and fractions. Students need to use a pronumeral to represent the unknown number They then need to write an equation and solve it to find the value of the unknown number.Solving math problems can intimidate eighth-graders. The key is to use the information you are given and then isolate the variable for algebraic problems or to know when to use formulas for geometry problems. Explain to students that you can use basic algebra and simple geometric formulas to solve seemingly intractable problems.

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